Dr. Grey performed an experiment to test how temperature affects activity levels in mice. She put one group of mice in a cold environment and another group of mice in a hot environment. Everything else about the two environments was the same, including the type and amount of food and water. She allowed the experiment to last for a few generations of mice and tested the activity levels of the different groups.

There was no change in the activity levels of the mice, but she noticed that the mice in the cold environment had much darker, thicker fur than the mice in the hot environment. What scientific question could she ask based on her results?
A.
Which group of mice is the most attractive?
B.
Do the mice in the cold environment run faster than the mice in the hot environment?
C.
Does temperature have an effect on fur color and thickness in mice?
D.
Does food type have an effect on fur color and thickness in mice?

A) acceleration. this seems to be the one that makes sense.

Simple harmonic motion wind energy circulation best answer from the choices

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s