A fisherman’s boat moves up and down periodically due to water waves. The boat travels from its highest to its lowest point, a vertical distance of 0.60 m, in 2.0 s. The horizontal distance between wave crests is 7.0 m. (a) What is the period of the wave motion? (b) What is the frequency of the wave motion? (c) W

Complete question is;

A fisherman’s boat moves up and down periodically due to water waves. The boat travels from its highest to its lowest point, a vertical distance of 0.60 m, in 2.0 s. The horizontal distance between wave crests is 7.0 m. (a) What is the period of the wave motion? (b) What is the frequency of the wave motion? (c) What is the amplitude of each wave

A) Period = 4 s

B) Frequency = 0.25 Hz

C) Amplitude = 0.3 m

Explanation:

A) We are told that the distance it takes for the boat to travel from its highest to its lowest point is 2 s.

Thus, t = 2 s

Now, in waves, period (T) it the time between two successive waves.

This means that;

T = 2t

T = 2 × 2

T = 4 s

B) Also, the frequency(f) is given by the formula;

f = 1/T

f = 1/4

f = 0.25 Hz

C) We are given a vertical distance of 0.60 m from highest to lowest point of waves.

Now, amplitude is half of this distance.

Thus;

Amplitude(A) = 0.6/2

A = 0.3 m

increase masses, decrease separation

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.