A student falls off a cliff into the lake 54.0 m below. What is the final velocity of the student?

= -32.53 m / s

this velocity is directed downwards

Explanation:

This is a free fall exercise, let's use the expression

          = v_{oy}^{2} + 2 g (y -yo)

where we are assuming that there is friction with the air, as the body falls its initial velocity is zero

         v_{oy} = √ 2g (y - y₀)

let's calculate

         v_{y} = √ (2 9.8 (0-54.0))

          = -32.53 m / s

this velocity is directed downwards

correct it is c.) b b

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.