A frog jumps to the left with an average speed of 1.8

m
s
1.8
s
m

1, point, 8, start fraction, start text, m, end text, divided by, start text, s, end text, end fractionfor
0.55

s
0.55s0, point, 55, start text, s, end text.
What was the frog's displacement in meters?

Explanation:

Average velocity is the change of rate of displacement with respect to time;

Average velocity = Displacement/Time

Given

Average velocity of the frog = 1.8m/s

Time = 0.55s

Required

Displacement of the frog

Substitute the given parameters into the formula;

1.8 = displacement/0.55

cross multiply

Displacement = 1.8*0.55

Displacement = 0.99 m

Hence the frog's displacement is 0.99m

i would say