A tennis ball is dropped from 1.48 m above the ground. It rebounds to a height of 0.956 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s
2
. (Let
down be negative.)
Answer in units of m/s.

v = 5.38 m/s

Explanation:

Given that,

A tennis ball is dropped from 1.48 m above the  ground, d = 1.48 m

It rebounds to a height of 0.956 m

We need to find the velocity of the ball when it hits the ground. Using equation of kinematics as follows :

So, when the ball hits the ground, its velocity is 5.38 m/s.

it is a negative acceleration

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