PLEAS HELP A jet makes a landing traveling due east with a speed of 120 m/s. If the jet comes to rest in 13.5 s , what’s the magnitude of its average acceleration?
Part B: What is the direction of its average acceleration? (North, south, east, west??)

8.89 m/s² west

Explanation:

Assume east is +x.  Given:

v₀ = 120 m/s

v = 0 m/s

t = 13.5 s

Find: a

v = at + v₀

0 m/s = a (13.5 s) + 120 m/s

a = -8.89 m/s²

a = 8.89 m/s² west

in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

explanation:

v=uf/(u-f)

= 5.-10/(5+10) convex lens has negative focal length