A bowling ball is launched from the top of a building at an angle of 35° above the horizontal with an initial speed of 15 m/s. The ball lands on the ground 2.9 s after it is launched. What is the height of the building (in m)?

Let be the height of the building and thus the initial height of the ball. The ball's altitude at time is given by

where is the acceleration due to gravity.

The ball reaches the ground when after . Solve for :

so the building is about 16 m tall (keeping track of significant digits).

r = ρ x length / area  

ρ = r x area / length  

ρ is in ohm-meters  

in basic units, it is m³kg/s³a²  

i think this is it.