company uses a ramp to slide boxes of parts to a shippingarea. Each box weighs about 10 kilograms. When sliding downthe ramp, the boxes accelerate at a speed of 0.1 m/sec2. What isthe force acting on each box? For this problem, ignore theeffects of friction acting on each box.

Fₓ = 1 N

Explanation:

For this exercise let's use Newton's second law, in this case our reference system has an axis parallel to the plane, we will call it the x-axis and we assume that the downward direction is positive, an y- axis perpendicular to the plane. Let's write Newton's second law for each axis

x axis

        Wₓ = m a

y Axis

        N - W_y =

        N = W_y

let's use trigonometry to find the components of the weight

         sin θ = Wₓ / W

         Wx = W sin  θ

          cos  θ = W_y / W

         W_y = W cos  θ

we substitute

        Fₓ = mg sin  θ = m a

        Fₓ = 10 0.1

        Fₓ = 1 N

This is the force that makes the box slide down and a component of the box's weight.

f is prop to m1xm2 double m1 double force

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..