A runner traveling with an initial velocity of 1.7 m/s accelerates at a constant rate of 1.2 m/s2 for a time of 6 seconds. What distance does the runner cover during this process?

31.80m

Explanation:

Given the following :

Initial Velocity (u) = 1.7m/s

Acceleration (a) = 1.2m/s²

Time (t) = 6seconds

Distance covered during the process:

Using the motion equation; calculate the final velocity (v)

v = u + at

v = 1.7 + (1.2*6)

v = 1.7 + 7.2

v = 8.9m/s

We can then find the distance covered during the process using :

v² = u² + 2aS

Where ; v = final velocity ; u = initial velocity

S = distance and a = acceleration

Hence,

8.9² = 1.7² + (2 × 1.2 × s)

8.9² = 2.89 + (2.4 × s)

79.21 = 2.89 + 2.4s

79.21 - 2.89 = 2.4s

76.32 = 2.4s

s = 76.32 / 2.4

s = 31.8m

increasing transnational kinetic energy. because the transnational kinetic energy formula consists of only two variables, mass and velocity, increasing one of those properties is the only way to increase an object's transnational kinetic energy. increases to mass and velocity, however, do not have the same impact.

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