A cricket batsman hits a ball at a speed of 27m/s at an angle of 60 degrees to the horizontal. How far away would you have to stand in order to catch it (assuming you want to catch it just before it hits the ground)?

64.4 m

Explanation:

First, find how long it takes to land.  Given in the y direction:

Δy = 0 m

v₀ = 27 m/s sin 60° ≈ 23.4 m/s

a = -9.8 m/s²

Find: t

Δy = v₀ t + ½ at²

0 m = (23.4 m/s) t + ½ (-9.8 m/s²) t²

t = 4.77 s

Next, find how far it travels in that time.  Given in the x direction:

v₀ = 27 m/s cos 60° = 13.5 m/s

a = 0 m/s²

t = 4.77 s

Find: Δx

Δx = v₀ t + ½ at²

Δx = (13.5 m/s) (4.77 s) + ½ (0 m/s²) (4.77 s)²

Δx = 64.4 m

b

explanation:

step-by-step explanation:

we are given

we have to simplify it

firstly, we will factor it

now, we can cancel like terms

now, we can combine it

so, we get