Physics, 20.09.2020 03:01, poweradampower
Given two vectors A⃗=4.30i^+7.20j^ A → = 4.30 i ^ + 7.20 j ^ and B⃗=5.20i^−2.30j^ B → = 5.20 i ^ − 2.30 j ^ , find the scalar product of the two vectors A⃗ A → and B⃗ B → .
Answers: 1
Physics, 22.06.2019 16:30, CadenSkinner2003
Place several e-field sensors at a few points on different equipotential lines, and look at the relationship between the electric field and the equipotential lines. which statement is true? 1-at any point, the electric field is perpendicular to the equipotential line at that point, and it is directed toward lines of higher voltages. 2-at any point, the electric field is perpendicular to the equipotential line at that point, and it is directed toward lines of lower voltages. 3-at any point, the electric field is parallel to the equipotential line at that point.
Answers: 1
Physics, 23.06.2019 06:40, BobreyesV20
12. ritu obtained a distinct image of a distant tree on the screen with the of a concave mirror. to find the focal length of the mirror she has to measure the distance between: (a) mirror and the tree. (b) screen and the tree.(c) mirror and the screen. (d) mirror and tree as well as between screen and the tree.
Answers: 2
Physics, 23.06.2019 20:20, something69
10. a person with a mass of 15 kg is walking uphill at a velocity of 2 m/s. what is the walker's momentum? a. 15 kg-m/s b. 30 kg-m/s c. 10 kg-m/s d. 13 kg-m/s 16. two bouncy balls colliding with each other is an example of what type of collision? a. inelastic collision b. elastic collision c. parallel collision d. mass collision 20 which of the following is considered to be a vector? a. temperature b. mass c. velocity d. time
Answers: 3
Physics, 24.06.2019 00:50, Qwerty2771
Scientists studying an anomalous magnetic field find that it is inducing a circular electric field in a plane perpendicular to the magnetic field. the electric field strength 1.5 m from the center of the circle is 6.5 mv/m.
Answers: 1
Given two vectors A⃗=4.30i^+7.20j^ A → = 4.30 i ^ + 7.20 j ^ and B⃗=5.20i^−2.30j^ B → = 5.20 i ^ − 2...
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