Question 1) A 2kg ball travelling horizontally at 2 m s - ¹ rebounds horizontally off a wall at the same speed, what is the change in momentum? Question 2) Two 5kg bodies approach each other, both having speed of 2 ms-¹. What is the total momentum? Please answer quick!

1) The change in momentum of the ball is 8 kgm/s

2) The total momentum of the bodies is 20 kgm/s

Explanation:

1)

Given;

mass of the ball, m = 2 kg

initial velocity of the ball, v₁ = 2 m/s

final velocity of the ball, v₂ = -2 m/s (the ball rebounds)

The change in momentum of the ball is given by;

ΔP = Δmv

ΔP = mv₁ - mv₂

ΔP = m(v₁ - v₂)

ΔP = 2(2 - (-2))

ΔP = 2(2 + 2)

ΔP = 8 kgm/s

2)

Given;

mass of the first body, m₁ = 5kg

mass of the second body, m₂ = 5kg

speed of the first body, v₁ = 2 m/s

speed of the second body, v₂ = 2 m/s

The total momentum of the bodies is given by

P = m₁v₁ + m₂v₂

P = (5 x 2) + (5 x 2)

P = 20 kgm/s

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the answer is a. the yacht traveled from the dock north to the 200-meter marker in the bay in less than 5 minutes, giving the passengers several more hours to fish.

im doing peak rn so sry if its wrong