Assume the lens-to-retina distance of the human eye is 2.00 cm. Calculate the power, P, in diopters, of the eye when viewing an object 3.5 m away.

The power of the eye is 50.29 D

Explanation:

Given;

distance between the lens and retina, d₁ = 2 cm = 0.02 m

distance between the object and lens, d₀ = 3.5 m

The power of the eye is given by;

where;

f is the focal length of the eye's lens

For a clear view, the distance between the lens and retina must be equal to distance between the lens and the image.

Therefore, the power of the eye is 50.29 D

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)