Physics, 06.09.2020 02:01, vicinimlv19

This is one I don’t understand ? How do you calculate formula ? Can you show all step

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answered: kell22wolf

Net force = 13.36 N

Explanation:

Recall the formula for the force between two charges q1 ans q2 separated a distance "d" based on Coulomb's Law:

$F_C=k\,\frac{q_1\,*\,q_2}{d^2}$

so, we need to calculate the force exerted on the charge 10 micro Coulombs by the 20 micro-Coulombs charge as they are separated 0.8 meters (haf the distance of the original two charges.

Notice that charges q1 and q3 are both positive charges so the force we obtain will be pointing in the direction towards charge q2. The magnitude of this is:

$F_{13}=k\,\frac{20\,\,10^{-6}\,*\,10\,\,10^{-6}}{0.8^2}=9\,\,10^{9}\,\frac{200\,\,10^{-12}}{0.8^2}= 2812.5 \,\,10^{-3} \,N = 2.8125 \,\,N$

We can calculate now the force exerted by charge q2 on charge q3 using the same reasoning, and noticing that since charge q2 is negative, the force on q3 will be of attraction, then also pointing in the direction towards q2:

$F_{23}=k\,\frac{75\,\,10^{-6}\,*\,10\,\,10^{-6}}{0.8^2}=9\,\,10^{9}\,\frac{750\,\,10^{-12}}{0.8^2}= 10546.875 \,\,10^{-3} \,N = 10.547 \,\,N$

Now, we need to add both forces to get the final force (recall they are both in the same direction):

Net force = 10.547 N + 2.813 N = 13.36 N

answered: Guest

$efficiency \: = \frac{useful \: energy \: output}{total \: energy \: input} \ \times$ $100$ therefore, the efficiency is: $\frac{222}{222} \times 100$ $= 100\%$

answered: Guest

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

$x(t)=ax(x-6)$

where $a$ is unknown. because the position is parabolic, there is symmetry about the midpoint at $t=3$ , and we know that

$x(3)=10\implies -9a=10\implies a=-\dfrac{10}9$

so that the position function is

$x(t)=-\dfrac{10}9x(x-6)$

which means the velocity is

$v(t)=\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac{20}9x+\dfrac{60}9$

then the total distance traveled is

$\displaystyle\int_{t=0}^{t=6}|v(t)|\,\mathrm dt=\left\{\int_{t-0}^{t=3}-\int_{t=3}^{t=6}\right\}v(t)\,\mathrm dt=20$

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at $x=0$ and ends at $x=0$ , so its displacement is 0.

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