evaluate the numerical value of the vertical velocity of the car at time t=0.25 s using the expression from part d, where y0=0.75m, α=0.95s^-1, and w=6.3s^-1

The numerical value of the vertical velocity of the car at the given time is 4.91 m/s.

The given parameters;

The final angular velocity of the car at the given time is calculated as;

The numerical value of the vertical velocity of the car at the given time is calculated as;

Thus, the numerical value of the vertical velocity of the car at the given time is 4.91 m/s.

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Given :

Displacement , y = 0.75 m .

Angular acceleration , .

Initial angular velocity , .

To Find :

The value of vertical velocity after time t = 0.25 s .

Solution :

By equation of circular motion is given by :

Putting all given values we get :

Now , vertical velocity is given by :

Therefore , the numerical value of the vertical velocity of the car at time t=0.25 s is 4.90 m/s .

Hence , this is the required solution .

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.