Bacteria vary somewhat in size, but a diameter of 2.3 m is not unusual. A. What would be the volume (in cubic centimeters) of such a bacterium, assuming that it is spherical?Express your answer using two significant figures. B. What would be the surface area (in square millimeters) of such a bacterium, assuming that it is spherical?

a) 6.4 x 10^-12 cm^3

b) 17 x 10^-6 mm^2

Explanation:

The complete question is...

Bacteria vary somewhat in size, but a diameter of 2.3 m is not unusual.

A. What would be the volume (in cubic centimeters) of such a bacterium, assuming that it is spherical? Express your answer using two significant figures.

B. What would be the surface area (in square millimeters) of such a bacterium, assuming that it is spherical?

Diameter of the bacteria d = 2.3 μm

Radius r = d/2 = 2.3/2 = 1.15 μm

The shape is assumed to be spherical

a) The volume = volume of a sphere =

V = = 6.3715 μm^3

1 μm^3 = 10^-12 cm^3

6.3715 μm^3 = 6.3715 x 10^-12 cm^3

==> 6.4 x 10^-12 cm^3

b) The surface area =

A = 4 x 3.142 x = 16.62 μm^2

1 μm^2 = 10^-6 cm^2

16.62 μm^2 = 16.62 x 10^-6 mm^2

==> 17 x 10^-6 mm^2

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.