You begin sliding down a 15° ski slope. Ignoring friction and air resistance, how fast will you be moving after 10 s? Please express your answer in meters per second (m/s). Thank you in advance!

25.4 m/s.

Explanation:

0+2.54×10=25.4m/s

Taking the x-coordinate to be parallel, and moving down the ramp or in other words, moving to the right will be somewhat positive.

Solution:

So...

Use the formula [ fv = iv + at ] when iv = 0, a = 2.54, and t = 10

Therefore, the answer is 25.4m/s

Best of Luck!

i don't understand. explain it clearly

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west