A baseball is thrown horizontally at 46 m/s. The ball slows down at a rate of 5 m/s2. How long is the ball in the air before coming to rest?

Explanation:

Using one of the equation of motion v = u + at where;

v is the final velocity = 0m/s (the ball comes to rest after throw)

u is the initial velocity = 46m/s

a is the acceleration = -5m/s² (the body decelerates)

t is the time taken by the ball in air

substituting the given parameters into the formula to get t, we will have;

0 = 46 +(-5)t

0 = 46 - 5t

subtract 46 from both sides

0-46 = 46-5t-46

-46 = -5t

Divide both sides by -5

-46/-5 = -5t/-5

t = 46/5

t = 9.2seconds

Hence it will take the ball 9.2seconds in the air before coming to rest.

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explanation:

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