When 10 N force applied at 30 degrees to the end of a 20 cm handle of a wrench, it was just able to loosen the nut. What magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle

Explanation:

To get the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle, we will have to resolve the force perpendicular to the wrench. Torque is the turning effect of a body or force about a point. It is similar to moments.

Torque = Force * radius

Note that the force must be perpendicular to the wrench. On resolving the force perpendicularly to the wrench, we will have to resolve the force to the vertical.

Fy = Fsinθ

Fy = 10sin30°

Fy = 10 * 0.5

Fy = 5N

Torque = Fy * r

Given Fy = 5N and r = 20cm = 0.2m

Torque = 5 * 0.2

Torque = 1Nm

Hence the magnitude of the force would require to just loosen the nut, if the force apply perpendicularly at the end of the handle is 5N

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explanation:

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