If the voltage across the plates is increasing at the rate of 220 V/s, what is the displacement current in the capacitor

Complete Question

A parallel-plate capacitor has square plates 20 cm on a side and 0.50 cm apart. If the voltage across the plates is increasing at the rate of 220 V/s, what is the displacement current in the capacitor?

The value is  

Explanation:

From the question we are told that

       The  length and breath of the square plate is  

        The  distance of separation between each plate is

       The rate of voltage  increase is  

Generally the charge on the plate is mathematically represented as

Now C is the capacitance of the capacitor which is mathematically represented as

Here A is the cross-sectional area which is mathematically represented as

=>  

=>  

So  

Now the change of the charge flowing through the plates with time is mathematically represented as

So  

Generally  

So

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)