An iguana runs back and forth along the ground. The horizontal position of the iguana in meters over time is shown below
Position
(meters)
10
8
6
4-
2
3
2
5
6
Time
(seconds)
1036

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j

the answer should be in the picture.