if a bicyclist, with initial velocity of zero, steadily gain speed until reaching a final velocity of 26m/s, how far away did she travel during the race (in the same amount of time?

Explanation:

Using one of the equation of motion to solve the question. According to the equation v² =u²+2as where;

v is the final velocity of the  bicyclist = 26m/s

u is the initial velocity of the  bicyclist = 0m/s

a is the acceleration due to gravity = 9.81m/s

s is the distance covered during travel

Substitute the given parameters into the formula above to get the distance traveled

26² = 0² + 2(9.81)s

676 = 19.62s

Divide both sides  by 19.62

676/19.62 = 19.62s/19.62

s = 34.46m

The distance traveled by the  bicyclist during the race is 34.46m

it breaks and dirupture other materials and other sencews from the bottom