Para concluir o seu trabalho, Ricardo utilizou uma lente com raio de curvatura de 100 cm para visualizar uma peça, qual a distancia da peça até a lente para se ter um aumento de 5 vezes? 1/f = 1/p + 1/p´

R = 2.f

A = y´/y = -p´/p = f/f-p

6 cos 34, 6 sin 34 trig

beta is electron from nucleus

something from nucleus has changed, but charge must be same for cons of charge

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

well clustered together.

points close on a scatter diagram