A student bikes to school by traveling first dN = 0.800 miles north, then dW = 0.300 miles west, and finally dS = 0.100 miles south. Similarly, let d--> W be the displacement vector corresponding to the second leg of the student's trip. Express d⃗ W in component form.
Express your answer as two numbers separated by a comma. Be careful with your signs.

66.8°

Explanation:

Calculating for tthe first leg

dNx = 0;

dNy = + 0.8 mi (0 , 0.8)

then for the second

dWx = - 0.3 mi;

dWy = 0 (-0.3 , 0)

then the third leg

dSx = 0;

dSy = - 0.1 mi (0 , -0.1)

So the displacement vector is

db = ( -0.3 , (0.8 - 0.1) )

db = ( -0.3 , 0.7)

Finding the magnitude i= √(0.3^2 + 0.7^2 )

= 0.76

So the direction is

စ= tan^-1( 0.7 / 0.3 ) = 66.8°

i am single too don't feel bad

the answer is b

explanation: