12. Ett metallblock (1,2 kg) glider med konstant hastighet längs en bordsyta. Blocket är via en lättrörlig
trissa fast vid en vikt (300 g) som drar i blocket.
1,2 kg
300 g
Bestäm friktionstalet mellan blocket och bordet.
Svar:
С
с

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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because if the tool that you are using is not balanced it there would be false mass.

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm