¿Cuál era el tiempo que tardó una persona que salió del kilómetro 6,2 y llegó al kilómetro 15,2 habiendo empleado una velocidad de 0,78 m/s? Graficar v (t) y x (t)

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.

can be answered using momentum.

momentum = p

p1= mass1 * velocity1

p1 = p2

therefore

p1 = 6kg * 4m/s

p1 = 24kgm/s

p2=m2 * v2

24 kgm/s = 7kg * v2

v2 = 24 kgm/s / 7kg

v2= 3.42 m/s

it doesn't. it was imagined up in the middle ages.

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .