A 0.16 pF parallel - plate capacitor is charged to 10 V. Then the battery is disconnected from the capacitor. When 1.00 107 electrons are now placed on the negative plate of the capacitor, the voltage between the plates changes by

The  value is  

Explanation:

From the question we are told that

    The  capacitance of the capacitor is

     The  voltage is  

    The number of electrons present on the negative plate is  

     Generally the charge on the positive plate at 10 Volt is mathematically represented as

     =>  

     =>    

Now the charge  on the plate when the electron where placed is evaluated as

Where e  is the charge on each electron with a value  

     =>    

      =>  

Generally the voltage between the two plate is evaluated as

=>    

=>      

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.

when jerome paddle in flowing river towards east the net speed of jerome will increase

so the net speed of jerome will be given as

now the speed of paul will be same as it is given as he is running on the ground

so

so here we can say since the speed of jerome is more so he will win the race

now as we know the distance so the time difference is given as

so jerome will reach first and the time difference will be 203.55 s or 3.4 min