The table displays the scores of students on a recent exam. Find the mean of the scores to the nearest 10th.
Score Number of Students
65
4.
70
2
75
2
80
1
85
7
90
5

Solution

x f fx

65 4 260

70 2 140

75 2 150

80 1 80

85 7 595

90 5 450

total N=21 Summation fx=1675

We know

Mean= Summation fx/N

=1675/21

=79.8

Hence, the required mean is 79.8 ans.

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