A light source radiates 60.0 W of single-wavelength sinusoidal light uniformly in all directions. Find the amplitude of the electric field of this light at a distance of 0.400 m from the bulb

E = 149.92 N/C

Explanation:

Given that,

The power emitted by a sinusoidal light is 60 W

Intensity is equal to the power per unit area. It can be given by :

The relation between the amplitude of the electric field and the intensity is given by :

Here, is the amplitude of the electric field

So, the amplitude of the electric field is 149.92 N/C.

explanation:

newton's third law, for every action there is an equal and opposite reaction.

the answer is f1 and d2 because if you put equal force on those two points the beam would balance trust me on this