B) A 5 kg mass is placed next to the end of the spring when it is compressed 0.60 m and the whole thing is let go. Neglecting the mass of the spring, how much potential energy has been lost by the mass when
it passes the point where the spring is compressed at 0.40 m?

it may be wrong but i think its a

find the surface area of the sphere to the nearest square unit. use a calculator.

a. 254 in.2

b. 64 in.2

c. 127 in.2

d. 1,018 in.2

the right answer is 0.3 meters per second

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm