The piston of a hydraulic elevator used for lifting trucks has a 0.3m radius. What pressure is required to lift a truck of 2500 kg mass? What force was applied to the small piston if it has a radius of 3cm?

1. 88370.45 N/

2. 2500 N.

Explanation:

Pressure, P, is define as the force, F, per unit area, A, applied on/ by an object.

i.e P =

1. The area, A, of the piston of the hydraulic elevator can be determined by;

A =

where r is the radius of the piston.

A = ×

  = × 0.09

  = 0.2829

Pressure required to lift a truck of 2500 kg mass can be determined as;

P =

F = W = mg

  = 2500 × 10

  = 25 000 N

So that,

P =

  = 88370.45 N/

The pressure required is 88370.45 N/.

2. =

 Area of small piston =

                                   = ×

                                   = 0.02829

So that,

=

= 2500 N

The force applied to the small piston is 2500 N.

the one with the highest speed

0.93xc=0.93x3x10^8m/s

2.54cm is 1 inch

360seconds i 1 hr