A car moving 12.2 m / s starts to coast UP a frictionless 14.0 ° hill. What is its acceleration?

Explanation:

A car moving 12.2 m/s starts to coast up a frictionless 14.0-degree hill, what is its acceleration (Unit=m/s^2)? ... So the acceleration is -2.374m/s^2, meaning in the direction opposite to the velocity of the car.

like poles repel so keep pushing north to north and repels funny to see this

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card