50 g of pieces of brass are heated to 200 ° C and then placed in the aluminum container of a 50 g calorimeter containing 160 g of water. What is the equilibrium temperature, if the temperature of the container and the water is initially 20 ° C?

24.7°C

Explanation:

Heat lost by brass = heat gained by aluminum and water

-q = q

-mCΔT = mCΔT + mCΔT

-(50 g) (0.380 J/g/°C) (T − 200°C) = (50 g) (0.900 J/g/°C) (T − 20°C) + (160 g) (4.186 J/g/°C) (T − 20°C)

-(19 J/°C) (T − 200°C) = (45 J/°C) (T − 20°C) + (670 J/°C) (T − 20°C)

-(19 J/°C) (T − 200°C) = (715 J/°C) (T − 20°C)

-19 (T − 200°C) = 715 (T − 20°C)

-19T + 3800°C = 715T − 14300°C

18100°C = 734T

T = 24.7°C

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