A thin film with an index of refraction of 1.50 is placed in one of the beams of a Michelson interferometer. If this causes a shift of 8 bright fringes in the pattern produced by light of wavelength 540 nm, what is the thickness of the film?

The thickness of the film is 4.32 μm.

Explanation:

Given;

index of refraction of the thin film on one beam, n₂ = 1.5

number of  bright fringes shift in the pattern produced by light, ΔN = 8

wavelength of the Michelson interferometer, λ = 540 nm

The thickness of the film will be calculated as;

where;

n₁ and n₂ are the index of refraction on the beam

L is the thickness of the film

Therefore, the thickness of the film is 4.32 μm.

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