A vertical tube one meter long is open at the top. It is filled with 75 cm of water. If the velocity of sound is 344 m/s, what will the fundamental resonant frequency be (in Hz)?

344Hz

Explanation:

First we need to more that the frequency will inky resonate in the portion not containing water. If the total length is 1m and the filled with water up to 75cm, the length of the air column will be 100cm - 75cm = 25cm

Fundamental frequency of a closed pipe fo = V/4L

V is the velocity of sound in air

L is the length of the air column

Given V = 344m/s

L = 25cm = 0.25m

fundamental resonant frequency = 344/4(0.25)

= 344/1

= 344Hz

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