A pump is to deliver 10, 000 kg/h of toluene at 1140C and 1.1 atm absolute pressure from the Reboiler of a distillation tower to the second distillation unit without cooling the toluene before it enters the pump. If the friction loss in the line between the Reboiler and the pump is 7 kN/m2. The density of toluene is 886 kg/m3. How far above the pump must the liquid be maintained to avoid cavitation

The NSPH values are used to calculate cavitation. The vapor pressure of the liquid is 1.114 atm.

The vapor pressure can be calculated by,

Where,

=available NPSH

    =absolute pressure at the inlet = 1.1 atm

    =average velocity at the inlet = 10, 000 kg/h

=fluid density = 886 kg/m3.  

g=acceleration of gravity = 9.8 m/s²

=vapor pressure of the fluid = ?

Put the values in the equation, we get

Therefore, the vapor pressure of the liquid is 1.114 atm.

To know more about  vapor pressure:

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3.4093

Explanation:

NPSHa = hatm + hel + hf +hva

the elevation head is the hel

friction loss head is hf

NPSHa is the head of vapour pressure of fluid

atmospheric pressure head is hatm

log₁₀P* =

log₁₀Pv =

= 4.07827 - 1343.943/333.377

=4.07827 - 4.0313009

= 0.0469691

we take the log

p* = 1.114218

we convert this value to get 111421.8

hvap = 111421.8 * 1/776.14 * 1/9.81

= 14.63

hatm = 1.1 *101325/1 * 1/9.81 *1/776.14

=14.64

hf = 7000/1 * 1/776.14 * 1/9.81

= 0.9193

NPSHa = 2.5

hel = 0.9193 + 2.5 + 14.63 - 14.64

hel = 3.4093

it is very well related to a lot of things but with my limited knowledge i can confidently say that the answer is space.

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.