3. A very light bamboo fishing rod 3.0 m long is secured to a boat at the bottom end. It is held in equilibrium by an 18 N horizontal force while a fish pulls on a fishing line

attached to the rod shown below. How much force F does the fishing line exert on the

rod? (3)

18 N

pivot

30°

1.8 m

3.0 in

The image in the attachment describes the situation of the fishing rod.

F = 10.8 N

Explanation: The image shows a fishing rod attached to an axis. To stay in equilibrium, Torque must be equal for the force of magnitude 18N and for the unknow force.

Torque (τ) is a measure of a force's tendency to cause rotation and, in physics, defined as:

τ = F.r.sin(θ)

F is the force acting on the object;

r is distance between where the torque is measured to where the force is applied;

θ is the angle between F and r;

For the fishing rod:

Assuming part (1) is related to unknown force:

Replacing the corresponding values:

F = 10.8

The fishing line exert on the the rod a force of 10.8N.

force is mass*acceleration.

we have a very small mass: 11.4*0.001 kg

if we want 0.035n of force, we need an acceleration:

0.035 = 11.4*0.001*a

a = 0.035/(11.4*0.001) m/s^2

1 the 4 is sig