A thick copper wire connected to a voltmeter surrounds a region of time-varying magnetic flux, and the voltmeter reads 6 volts. If instead of a single wire we use a coil of thick copper wire containing 20 turns, what does the voltmeter read

The voltmeter will read 120 volts

Explanation:

For a given magnetic field strength, undergoing a change in flux linkage with time. If a single wire has on it, due to this field an induced EMF of

E = -dΦ/dt

then, increasing the area of the single wire loop by using a wire of the same material containing N number of loops loops will increase the induced EMF to

E = -NdΦ/dt

where E is the induced EMF

N is the number of turns

dΦ/dt is the rate of change of the magnetic flux

From this, we can see that if the voltage reading due to the single thick copper wire is 6 volts, using a coil of thick copper wire containing 20 turns will give a reading of

==> E = 6 x 20 = 120 volts

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

ingenuity says that the answer is 2.7 m.