A square loop 24.0 cm on a side has a resistance of 6.10Ω. It is initially in a 0.665-T magnetic field, with its plane perpendicular to magnetic field B but is removed from the field in 40.0ms. Calculate the electric energy dissipated in this process.

Explanation:

It is given that,

Side of a square loop, l = 24 cm = 0.24 m

Resistance of loop, R = 6.1 ohms

Initial magnetic field is 0.665 T and final magnetic field is 0 as the field is removed in 40 ms

We need to find the electrical energy dissipated in this process.

Due to change in magnetic field, the loop will induce a voltage. The induced voltage is given by :

If I is induced current then,

Power is given by voltage times current. So,

Now, energy is given by the product of power and time. So,

Now putting all the values in above formula. So,

So, the electrical energy of is dissipated in this process.

the answer is to check all of them! they all apply well at least i think so!

f=ma newton

f=100x2.5=250n