if rain drops of equal size fall with terminal velocity of 0.50m/s. what will be the terminal velocity if the drops collaspe to form a big drop?

0.25m/s

Explanation:

m1v1 =m2 v2. law of conservation the of momentum. since they smash together to form a big drop M2 =2m1

m1*0.50m/s=2m1*v2

V2= m1*0.50m/s÷2m1

V2= 0.25m/s

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i really dont know but i will try okay.

so i think u would just add all them up and get your answer..