Two 15-Ω and three 25-Ω light bulbs and a 24 V battery are connected in a series circuit. What is the current that passes through each bulb?

Explanation:

Before we determine the amount of current in each bulb, we must first know that the same current flows in a series connected resistors. Since the Two 15-Ω and three 25-Ω light bulbs are connected in series, same current will flow in all of them.

According to Ohm's law, E = IRt where;

E is the supply voltage = 24V

I is the total current flowing in the circuit

Rt is the total equivalent resistance.

First, we need to calculate Rt.

Rt = 15Ω+15Ω+25Ω+25Ω+25Ω (Two 15-Ω and three 25-Ω light bulb in series)

Rt = 105Ω

From ohms law formula, I = E/Rt

I = 24/105

I = 0.229Amp

Since the total current in the circuit is 0.229A, therefore the amount of current that passes through each bulb is the same as the total current i.e  0.229A

3.2x10^7