During which two time intervals does the particle undergo equal displacement?

The correct answer to this question is b) AB & DE.

Explanation:

The two intervals represent equal displacement of the particle. Delta (x) is always 2. So you need to, average the initial and final velocities of each interval. Then to find total displacement, multiply by two.  

2 * [ (0 + 10)/2 ] = 10 for interval AB  

2 * [ (7 + 3)/2 ] = 10 for interval DE

need to see circuit to get time constant

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

-reverse card