A dentist using a dental drill brings it from rest to maximum operating speed of 382,000 rpm in 3.0 s. Assume that the drill accelerates at a constant rate during this time. A) What is the angular acceleration of the drill in rev/s2?
B) Find the number of revolutions the drill bit makes during the 2.6 s time interval. rev

a.

b.

Explanation:

The computation is shown below:

data provided in the question

The initial angular velocity   = 0 rev/s,

f = Final angular velocity = = 382000 rpm i.e = = 6,366.67

And time = t = 3.0s

Based on the above information

a. For angular acceleration of drill

b. For the number of revolutions

We simply applied the above formulas for determining each parts

probably not if net force is zero

answer///terminator or twilight zone;