A certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of What is the diameter of the wire in the fuse?

The value of the diameter of the wire is 0.45 mm.

Given that:

Current in the fuse = 1 Ampere

Current density = 620 A/cm²

Area of the wire =

Area =

Area = 1.613 x 10⁻³ cm²

Also, we know that:

10000 cm² = 1 m²

1.613 x 10⁻³ cm² = 1.613 x 10⁻⁷ m²

The area of a wire can be calculated as:

Area =

where, d = diameter

Substituting the values in the above equation, we get:

1.613 x 10⁻⁷ =

6.448 x 10⁻⁷ = 3.142 x d²

Hence, the value of d will be:

d² = 2.05 x 10⁻⁴

d =

d = 4.5 x 10⁻⁷

Thus, the value of the diameter of the wire is 0.45 mm.

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0.45 mm

Explanation:

The complete question is

a certain fuse "blows" if the current in it exceeds 1.0 A, at which instant the fuse melts with a current density of 620 A/ cm^2. What is the diameter of the wire in the fuse?

A) 0.45 mm

B) 0.63 mm

C.) 0.68 mm

D) 0.91 mm

Current in the fuse is 1.0 A

Current density of the fuse when it melts is 620 A/cm^2

Area of the wire in the fuse = I/ρ

Where I is the current through the fuse

ρ is the current density of the fuse

Area = 1/620 = 1.613 x 10^-3 cm^2

We know that 10000 cm^2 = 1 m^2, therefore,

1.613 x 10^-3 cm^2 = 1.613 x 10^-7 m^2

Recall that this area of this wire is gotten as

A =

where d is the diameter of the wire

1.613 x 10^-7 =

6.448 x 10^-7 = 3.142 x

=

d = 4.5 x 10^-4 m = 0.45 mm

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answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg