Solve the given parallel circuit by computing the desired quantities. I1 = amperes I2 = amperes I3 = amperes P1 = watts P2 = watts P3 = watts total current = amperes total power = watts

1. Current 1 (I1) is 2 A.

2. Current 2 (I2) is 4 A.

3. Current 3 (I3) is 1.3 A.

4. Power 1 (P1) is 48 W.

5. Power 2 (P2) is 96W.

6. Power 3 (P3) is 31.2 W.

7. Total current is 7.3 A.

8. Total power is 175.2 W.

Explanation:

Data obtained from the question include the following:

Voltage (V) = 24 V

Resistance 1 (R1) = 12 Ω

Resistance 2 (R2) = 6 Ω

Resistance 3 (R3) = 18 Ω

1. Determination of the current 1 (I1)

Voltage (V) = 24 V

Resistance 1 (R1) = 12 Ω

Current 1 (I1) =..?

V = I1R1

24 = I1 x 12

Divide both side by 12

I1 = 24/12

I1 = 2 A

Therefore, the current 1 (I1) is 2 A

2. Determination of the current 2 (I2)

Voltage (V) = 24 V

Resistance 2 (R2) = 6 Ω

Current 2 (I2) =..?

V = I2R2

24 = I2 x 6

Divide both side by 6

I2 = 24/6

I2 = 4 A

Therefore, the current 2 (I2) is 4 A

3. Determination of the current 3 (I3)

Voltage (V) = 24 V

Resistance 3 (R3) = 18 Ω

Current 3 (I3) =..?

V = I3R3

24 = I3 x 18

Divide both side by 18

I3 = 24/18

I3 = 1.33 A

Therefore, the current 3 (I3) is 1.3 A.

4. Determination of power 1 (P1)

Voltage (V) = 24 V

Current 1 (I1) = 2 A

Power 1 (P1) =..?

P1 = I1V

P1 = 2 x 24

P1 = 48 W

Therefore, power 1 (P1) is 48 W.

5. Determination of power 2 (P2)

Voltage (V) = 24 V

Current 2 (I2) = 4 A

Power 2 (P2) =..?

P2 = I2V

P2 = 4 x 24

P2 = 96 W

Therefore, power 2 (P2) is 96W.

6. Determination of power 3 (P3)

Voltage (V) = 24 V

Current 3 (I3) = 1.3 A

Power 3 (P3) =..?

P3 = I3V

P3 = 1.3 x 24

P1 = 31.2 W

Therefore, power 3 (P3) is 31.2 W.

7. Determination of the total current

Current 1 (I1) = 2 A.

Current 2 (I2) = 4 A.

Current 3 (I3) = 1.3 A

Total current =.?

Total current = I1 + I2 + I3

Total current = 2 + 4 + 1.3

Total current = 7.3 A

Therefore, the total current is 7.3 A.

8. Determination of the total power.

Power 1 (P1) = 48 W.

Power 2 (P2) = 96W.

Power 3 (P3) = 31.2 W.

Total power =..?

Total power = P1 + P2 + P3

Total power = 48 + 96 + 31.2

Total power = 175.2 W

Therefore, the total power is 175.2 W.

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i have found an answer to your question but use it as information.

information: because weak acids/bases have low concentration of hydrogen ions, the addition of water has a large impact on the ph. 2. a difference in 1 unit is a 10x difference in concentration for example; a liquid with ph of 3 is 10x more acidic than a liquid with a ph of 4. therefore, a liquid with a ph of 3 is stronger.

best of luck!