6. While standing on an ice surface (assume no friction), a 60 kg skater pushes against a wall with an average force of 240 N east for 0.360 s. Calculate the velocity
(magnitude and direction) of this student at 0.360 s.

1.44m/s West

Explanation:

Given the following :

Mass of skater = 60kg

Average force = 240N east

Time of = 0.360 seconds

The Velocity after 0.360seconds

Recall the relation:.

Force(f) * time(t) = mass (m) * (final Velocity(V) - initial velocity(u))

Where ; final Velocity(v) - initial velocity(u) = Magnitude of velocity(V)

Ft = mV

240 × 0.360 = 60 × V

60 × V = 86.4

V = 86.4 / 60

V = 1.44m/s

According to Newton's third law, to every action, there is an equal and opposite reaction.

The action force acts in the eastern direction hitting the wall with a force of 240N, therefore direction after hitting the wall will be in the opposite (western direction) direction, which is the direction of the reaction force

Therefore, velocity is 1.44ms West