.50-kg stone is dropped from rest at a height of 3.75 m. What impulse does gravity impart to this stone from the instant it is dropped until it hits the ground, assuming negligible air resistance

21.41 kg-m/s.

Explanation:

Data provided

Height = 3.75 m

Mass of stone = 2.50 kg

The computation of impulse is shown below:-

First we will compute the time using motion's equation  which is

as,

s indicates height

u indicates initial speed

t indicates time

Now, we will use the equation and put the values

t = 0.874 seconds

After computing the time now we will find put the impulse  which is

Now we will put the values into the above formula to reach the impulse

J = 21.41 kg-m/s.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.