How much heat had to be put in during the process to increase the internal energy of the gas by 2.00×104 JJ ?

Complete question:

The pv diagram in the figure below (see attached file) shows a process abc involving 0.920 of an ideal gas.

How much heat had to be put in during the process to increase the internal energy of the gas by 2.00×10⁴ J ?

The amount of heat required to increase the internal energy of the gas is 2,000 J

Explanation:

Work done in gas is given as;

W = ΔPV

The pressure of the gas at "a" = 2 x 10⁵ Pa

The pressure of the gas at "b" = 5 x 10⁵ Pa

The volume of the gas at "a" = 0.01 m³

The volume of the gas at "b" = 0.07 m³

The work done = (5 x 10⁵ Pa - 2 x 10⁵ Pa) x (0.07 m³ - 0.01 m³)

The work done = 3 x 10⁵ Pa x 0.06 m³

The work done = 18000 J

The work done = 1.8 x 10⁴ J

Determine, the amount of heat required to increase the internal energy of the gas by 2.00×10⁴ J.

1.8 x 10⁴ J + H = 2.00 x 10⁴ J

H = 2.00 x 10⁴ J - 1.8 x 10⁴ J

H = 0.2 x 10⁴ J

H = 2,000 J

Therefore,  the amount of heat required to increase the internal energy of the gas by 2.00×10⁴J is 2,000 J

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explanation: