If 62.9 cm of copper wire (diameter = 1.15 mm, resistivity = 1.69 × 10-8Ω·m) is formed into a circular loop and placed perpendicular to a uniform magnetic field that is increasing at the constant rate of 8.43 mT/s, at what rate is thermal energy generated in the loop?

The answer is ""

Explanation:

length of the copper wire:

L= 62.9 cm

r is the radius of the loop then:

area of the loop Is:

change in magnetic field is:

then the induced emf is:  

resistivity of the copper wire is:  1.69 × 10-8Ω·m

diameter d = 1.15mm

radius (r) = 0.5mm

hence the resistance of the wire is:

Power:

The final answer is:

current and voltage can both be different in different parts of a circuit so it matters where you place the ammeter and voltmete

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