A grating having 5000 lines/cm is used with light of wavelength 633 nm. How many total maxima (count central maxima plus all those on either side of the central maxima) are produced

The  total number of maxima produced is   maxima

Explanation:

From the question we are told that

    The number of lines per cm is  

      The wavelength of the light is  

Now the distance between the lines is mathematically evaluated as

substituting values  

              N/B - this  statement convert it from  cm to m

Generally the condition for diffraction i mathematically represented as  

at maximum  

here m is the  number of  maxima  

      Thus  making  m the subject we have

So    

=>          m  =3  

  Now the total number of maxima would include the bright fringe(3) and  dark fringe (3) plus the central maxima (1)

Thus  

        maxima

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.